How to Use the Python count() Method: A Complete Guide
Python is a high-level, interpreted programming language that has gained immense popularity across multiple domains such as data science, machine learning, and web development. Its simplicity, readability, and versatility make it an excellent choice for beginners and professionals alike. Python provides a vast standard library and built-in functions that simplify common programming tasks.
One of the useful built-in functions available in Python is the count() function. It helps you determine the number of times a specific element appears in sequences like lists, tuples, or strings. This function is particularly helpful when working with large datasets where you need to analyze the frequency of certain elements or values.
Understanding how to effectively use the count() function can enhance your data manipulation skills and optimize your coding solutions.
The count() function in Python is a built-in method that returns the number of times a specified element appears in a sequence, such as a list, tuple, or string. This makes it an essential tool when you need to track occurrences or measure the frequency of items within your data.
The function iterates over the sequence and counts every instance that matches the given argument. It then returns an integer representing the total count. If the element does not exist in the sequence, the function returns zero.
Counting elements is a fundamental operation in programming, especially when dealing with data analysis, validation, or filtering. The count() function simplifies this task by providing a concise and efficient way to get the frequency of elements without needing to write custom loops or complex conditions.
For example, in data processing, you might want to know how many times a particular value appears in a list of measurements. Or, you could use count() to find duplicate items in a collection or to tally specific characters in a string.
To use the count() function with lists or tuples, the syntax is straightforward:
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sequence.count(element)
The function returns an integer that represents how many times the element occurs in the sequence.
Consider a list of numbers:
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my_list = [1, 2, 3, 2, 4, 2, 5]
count_of_twos = my_list.count(2)
print(count_of_twos)
Output:
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3
Explanation: The count() function counts how many times the number 2 appears in my_list. Here, it appears three times, so the output is 3.
You can similarly use the count() function with tuples:
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my_tuple = (1, 1, 2, 3, 1, 4)
count_of_ones = my_tuple.count(1)
print(count_of_ones)
Output:
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3
Explanation: The function counts the number of times 1 appears in the tuple and returns 3.
The count() method is highly versatile and can be used in many scenarios:
Understanding these applications will help you leverage count() effectively in your Python programs.
The count() method in Python is widely used to determine how many times a particular substring appears in a string. This method is a built-in string method and is extremely useful for text analysis, searching, and parsing. The string count() method scans the entire string (or a specified section of it) and returns the number of non-overlapping occurrences of the substring you specify.
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string.count(substring, start=0, end=len(string))
The method returns an integer representing the number of times the substring occurs within the specified range of the string. If the substring is not found, it returns 0.
The count() method searches for non-overlapping occurrences of the substring. This means if the substring appears multiple times in an overlapping fashion, only distinct, separate occurrences will be counted. For example, consider the string “aaaa” and counting the substring “aa”. The substring “aa” can be found starting at index 0 and index 1 (overlapping). However, the count() method will only count the occurrences that do not overlap.
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text = “aaaa”
print(text.count(“aa”))
Output:
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2
Explanation: The method counts “aa” at positions 0-1 and 2-3. The overlapping occurrence starting at index 1 is not counted separately.
The substring is the target string whose occurrences you want to count within the main string. It can be a single character or multiple characters (even a full word). Examples of substrings: single character “a”, “x”, ” “, multiple characters “the”, “is”, “cat”.
This parameter defines the index position in the string where the method should begin its search. If omitted, the search starts at the beginning of the string (index 0).
Example:
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text = “hello world”
print(text.count(“o”, 5))
Output:
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1
Explanation: The substring “o” appears twice in the string, at indices 4 and 7. But since the search starts at index 5, only the occurrence at index 7 is counted.
This parameter specifies the index where the method should stop searching. The end index is exclusive, meaning it does not include the character at that position. If not provided, the search continues to the end of the string.
Example:
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text = “hello world”
print(text.count(“l”, 0, 5))
Output:
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2
Explanation: The substring “l” occurs three times in the whole string, but restricting the search to indices 0 through 4 (characters “hello”) counts only the first two occurrences.
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sentence = “Python is great. Python is easy to learn. Python is popular.”
count_python = sentence.count(“Python”)
print(“Python appears”, count_python, “times”)
Output:
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Python appears 3 times.
Explanation: The method counts the word “Python” appearing three times in the sentence.
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sentence = “Python is great. Python is easy to learn. Python is popular.”
count_python_partial = sentence.count(“Python”, 10, 40)
print(“Python appears”, count_python_partial, “times in the specified range”)
Output:
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Python appears 1 time in the specified range.
Explanation: When the search range is limited to characters between index 10 and 40, “Python” appears only once.
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text = “hello world”
count_l = text.count(“l”)
print(“The letter ‘l’ appears”, count_l, “times”)
Output:
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The letter ‘l’ appears 3 times.
Explanation: This example counts occurrences of a single character in the string.
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sentence = “Count the spaces in this sentence.”
space_count = sentence.count(” “)
print(“Number of spaces:”, space_count)
Output:
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Number of spaces: 5
Explanation: Spaces are also characters and can be counted just like letters.
If you call count() with an empty string “”, Python returns the number of possible positions between characters plus one.
Example:
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text = “abc”
print(text.count(“”))
Output:
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4
Explanation: There are 4 positions where an empty substring can be found: before ‘a, between ‘a and ‘b’, between ‘b’ and ‘c’, and after ‘c’.
The count() method is case sensitive. This means that searching for “Python” and “python” will yield different results.
Example:
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text = “Python python PyThOn”
print(text.count(“Python”))
print(text.count(“python”))
Output:
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1
1
Explanation: “Python” with uppercase P appears once, and “python” with lowercase p also appears once.
The count() method supports Unicode characters and counts substrings exactly as they appear, including emojis or accented characters.
Example:
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text = “naïve naïve naïve”
print(text.count(“ï”))
Output:
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3
Explanation: The special character ï is counted three times.
You can combine count() with other string methods for more complex text processing tasks. For instance, you may want to count a substring in a case-insensitive way by converting the string to lowercase first.
Example:
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text = “Python is fun. Python is easy.”
count_case_insensitive = text.lower().count(“python”)
print(“Python appears (case-insensitive):”, count_case_insensitive)
Output:
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Python appears (case-insensitive): 2
Explanation: The string is converted to lowercase before counting to ignore case differences.
While count() only accepts one substring at a time, you can count multiple substrings by calling it multiple times and aggregating the results.
Example:
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text = “apple banana apple orange banana apple”
count_apple = text.count(“apple”)
count_banana = text.count(“banana”)
print(“Apple:”, count_apple, “Banana:”, count_banana)
Output:
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Apple: 3 Banana: 2
The count() method is implemented efficiently in Python, but there are cases where its use might be expensive, especially on very large strings or in loops. If you need to count multiple substrings frequently or work with large data, consider using specialized libraries or tools optimized for text processing, such as collections. Counter for tokens or regular expressions for pattern matching.
The count() method is a powerful and easy-to-use tool to find how many times a substring appears in a string. By understanding its parameters and behavior, you can harness it for tasks such as text analysis, validation, and frequency measurement. Key takeaways: it counts non-overlapping occurrences of the substring, can limit the search with optional start and end parameters, is case sensitive, supports Unicode and special characters, and calling with an empty substring returns the number of possible positions in the string.
The count() method in Python lists is a simple yet powerful tool to find how many times a specific element appears in a list. Lists are one of Python’s fundamental data structures, widely used to store ordered collections of items, which can be of any data type — integers, strings, other lists, tuples, or even complex objects.
in Python
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list.count(value)
The method returns an integer representing how many times the specified value appears in the list. If the value is not found, it returns 0.
The count() method iterates over every element in the list, comparing each one to the value passed as an argument. For each match, it increments an internal counter. Once the entire list has been checked, it returns the total count. This method uses equality comparison (==) to check for matches.
Because of this, if the list contains complex objects (e.g., user-defined classes), the equality comparison behavior (__eq__ method) of those objects affects the result of count().
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numbers = [1, 2, 3, 2, 2, 4, 5]
count_twos = numbers.count(2)
print(“Number 2 appears”, count_twos, “times”)
Output:
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Number 2 appears 3 times.
Explanation: The number 2 appears three times in the list.
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fruits = [“apple”, “banana”, “apple”, “orange”, “banana”]
count_apple = fruits.count(“apple”)
print(“Apple appears”, count_apple, “times”)
Output:
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Apple appears 2 times.
Explanation: The string “apple” occurs twice.
Lists can contain tuples or other objects. The count() method can count tuples exactly by matching the whole tuple element.
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cities = [(“Paris”, 1), (“London”, 2), (“Paris”, 1), (“Rome”, 3)]
count_paris = cities.count((“Paris”, 1))
print(“Paris tuple appears”, count_paris, “times”)
Output:
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Paris tuple appears 2 times.
Explanation: The tuple (“Paris”, 1) appears twice in the list.
The count() method uses equality comparison (==). If you try to count a value of a different type than elements in the list, it will return 0. For example:
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numbers = [1, 2, 3, 4]
print(numbers.count(“2”)) # Counting string “2” in list of integers
Output:
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0
Explanation: “2” (string) is not equal to 2 (integer), so count returns 0.
If your list contains mutable objects like lists or custom classes, count() depends on how equality is defined. If you have a custom class without an __eq__ method, each object is only equal to itself, so duplicates won’t count unless they are the same object.
Example:
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class Person:
def __init__(self, name):
self.name = name
p1 = Person(“Alice”)
p2 = Person(“Alice”)
people = [p1, p2, p1]
print(people.count(p1)) # Output: 2
print(people.count(p2)) # Output: 1
Explanation: p1 and p2 have the same content but are different objects. Count () counts exact matches.
The count() method accepts exactly one argument. Passing more than one argument raises a TypeError.
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numbers = [1, 2, 3]
# Wrong usage
numbers.count(1, 2) # Raises TypeError
Always ensure only a single argument is passed.
If your list contains nested lists, the count() method compares the whole nested list for equality.
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nested = [[1, 2], [3, 4], [1, 2]]
print(nested.count([1, 2]))
Output:
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2
Explanation: The list [1, 2] appears twice.
For very large lists, repeatedly calling count() can be inefficient since it scans the entire list each time. In such cases, consider using collections. Counter or other optimized data structures.
Tuples are immutable sequences in Python and support the count() method as well. They work almost identically to lists to count elements.
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tuple.count(value)
Returns how many times the value appears in the tuple.
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numbers = (1, 2, 3, 2, 2, 4, 5)
count_twos = numbers.count(2)
print(“Number 2 appears”, count_twos, “times in tuple”)
Output:
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Number 2 appears 3 times in the tuple.
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fruits = (“apple”, “banana”, “apple”, “orange”, “banana”)
count_apple = fruits.count(“apple”)
print(“Apple appears”, count_apple, “times in tuple”)
Output:
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Apple appears 2 times in the tuple.
In many data science and analysis tasks, it is often required to find the frequency of items in datasets stored as lists or tuples. The count() method provides a quick way to do this for individual elements. For example, counting how many times a user ID appears in a list of transactions can help detect duplicates or popular items.
The count method can be used to detect duplicate values in lists or tuples. If an element’s count is greater than 1, it is duplicated.
Example:
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data = [1, 2, 2, 3, 4, 5, 5, 5]
duplicates = [item for item in set(data) if data.count(item) > 1]
print(“Duplicates are:”, duplicates)
Output:
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Duplicates are: [2, 5]
Before processing data, it’s often important to check if certain values exist or how frequently they appear. Using count() can help validate the presence or absence of key values.
You can also build logic that changes behavior based on how many times an element appears. For example, alerting if a sensor reading exceeds a threshold number of times.
You can loop through a list or tuple and use the count() method to find the frequencies of all elements.
Example:
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items = [“a”, “b”, “a”, “c”, “b”, “a”]
for item in set(items):
print(f”{item}: {items.count(item)}”)
Output:
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a: 3
b: 2
c: 1
Example:
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scores = [10, 20, 10, 30, 10, 40]
If scores.count(10) > 2:
print(“Score 10 appears more than twice!”)
Output:
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Score 10 appears more than twice!
The method can be used inside list comprehensions to filter elements based on frequency.
Example:
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data = [1, 2, 2, 3, 3, 3]
Unique = [x for x in data if data.count(x) == 1]
print(“Unique items:”, unique)
Output:
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Unique items: [1]
Since count() iterates over the entire list or tuple every time it’s called, repeated calls inside loops can be inefficient for large datasets.
Cannot Count Multiple Values at once. Count () accepts only one argument. If you want to count multiple different values, you must call it repeatedly or use other methods like collections. Counter.
count() matches elements exactly and does not support pattern or partial matching. For advanced searching, regular expressions or custom logic are needed.
The Counter class from the collections module is optimized for counting hashable objects and provides a dictionary-like object with counts of all elements. It is more efficient when you want to count the frequencies of all elements once.
Example:
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from collections import Counter
data = [1, 2, 2, 3, 3, 3]
counter = Counter(data)
print(counter)
print(counter[2]) # Count of 2
Output:
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Counter({3: 3, 2: 2, 1: 1})
2
You can count elements meeting a condition using list comprehensions with len().
Example:
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data = [1, 2, 3, 4, 5, 6]
count_even = len([x for x in data if x % 2 == 0])
print(“Even numbers count:”, count_even)
Output:
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Even numbers count: 3
Count how many times a certain error code appears in a list of log entries.
Counting how many times a product appears in an inventory list to detect stock levels.
Counting votes for each candidate in a list of votes.
Counting how many times each answer appears in the survey response data.
Now, let’s dig even deeper into advanced uses, edge cases, performance optimizations, and real-world scenarios.
When your list or tuple contains objects of user-defined classes, count() relies on the equality operator ==, which by default compares object identity (memory address). To make count() behave as expected, you should override the __eq__ and __hash__ methods in your class.
Example:
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class Product:
def __init__(self, name, price):
self.name = name
self.price = price
def __eq__(self, other):
if isinstance(other, Product):
return self. Name == other.name and self.price == other.price
return False
def __hash__(self):
return hash((self.name, self.price))
p1 = Product(“Pen”, 1.20)
p2 = Product(“Pen”, 1.20)
p3 = Product(“Notebook”, 2.50)
products = [p1, p2, p3, p1]
print(products.count(p1)) # Output: 3 (counts equal objects)
print(products.count(Product(“Pen”, 1.20))) # Output: 3
Why override __eq__ and __hash__?
What if your list contains nested lists or tuples, or dictionaries?
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nested_list = [[1, 2], [3, 4], [1, 2], [5, 6]]
print(nested_list.count([1, 2])) # Output: 2
Since lists are mutable, equality checks the contents element-wise. This works as expected for nested lists or tuples.
But dictionaries inside lists are only equal if their key-value pairs match exactly.
Python lists and tuples can contain heterogeneous data types.
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mixed = [1, “1”, 1.0, True, (1,), [1], {“one”: 1}]
print(mixed.count(1)) # 3 (1, 1.0, True are equal to 1)
print(mixed.count(“1”)) # 1
print(mixed.count((1,))) # 1
print(mixed.count([1])) # 1
print(mixed.count({“one”:1})) # 1
Note:
count() method runs in O(n) time — it has to check every element.
For small lists, this is trivial. For very large lists, repeated calls to count() inside loops can cause performance bottlenecks.
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items = [1] * 100000 + [2] * 100000 + [3] * 100000
for x in set(items):
print(f”{x}: {items.count(x)}”)
Here, count() is called once for each unique item. Each call is O(n), so total complexity is O(n * k), where k is the number of unique items.
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from collections import Counter
items = [1] * 100000 + [2] * 100000 + [3] * 100000
counter = Counter(items)
For the item, count in the counter.items():
print(f”{item}: {count}”)
Counter calculates frequencies once in O(n), then provides constant-time access to counts.
If you prefer not to use collections, a manual dictionary count can be implemented:
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items = [1, 2, 3, 2, 1, 1]
counts = {}
For item in items:
counts[item] = counts.get(item, 0) + 1
print(counts)
This method is also O(n) and often faster than multiple calls to count().
Counting how many times a word appears in a text document or list of words.
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text = “To be or not to be that is the question to be or not to be”
words = text.lower().split()
word = “be”
print(words.count(word)) # Output: 4
Using a Counter is preferred for counting all words efficiently.
You might want to keep only elements that appear once in a list:
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data = [1, 2, 2, 3, 3, 3, 4]
unique = [x for x in data if data.count(x) == 1]
print(unique) # Output: [1, 4]
This removes duplicates by checking count == 1.
Counting votes represented by a list of candidate names:
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votes = [“Alice”, “Bob”, “Alice”, “Charlie”, “Bob”, “Bob”]
candidates = set(votes)
For a candidate among candidates:
print(f”{candidate}: {votes.count(candidate)} votes”)
For large elections, use Counter to improve performance.
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sensor_data = [10, 12, 10, 10, 13, 12, 10]
threshold = 3
reading = 10
if sensor_data.count(reading) >= threshold:
print(f”Reading {reading} appears frequently”)
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lst = [1, 2, 3]
lst.count(1, 2) # Raises TypeError: count() takes exactly one argument (2 given)
Fix: Only pass one argument.
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lst = [“apple”, “applesauce”, “applepie”]
print(lst.count(“apple”)) # Output: 1 (exact match only)
Count () does not support substring or pattern matching.
Counter requires hashable items. Lists are unhashable and cause errors:
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from collections import Counter
lst = [[1, 2], [1, 2], [3, 4]]
Counter(lst) # Raises TypeError: unhashable type: ‘list’
Workaround: Convert lists to tuples.
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lst = [(1, 2), (1, 2), (3, 4)]
counter = Counter(lst)
print(counter)
Method | Use Case | Time Complexity | Supports Unhashable | Returns |
list.count(value) | Single value count | O(n) | Yes | int |
tuple.count(value) | Single value count | O(n) | Yes | int |
Counter | Count the frequencies of all elements | O(n) | No | dict |
list comprehension + len() | Count by condition | O(n) | Yes | int |
Sometimes you want a variation of count() with custom matching logic.
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def count_case_insensitive(lst, val):
return sum(1 for x in lst if isinstance(x, str) and x.lower() == val.lower())
fruits = [“Apple”, “apple”, “APPLE”, “Banana”]
print(count_case_insensitive(fruits, “apple”)) # Output: 3
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def count_by_predicate(lst, predicate):
return sum(1 for x in lst if predicate(x))
numbers = [1, 2, 3, 4, 5, 6]
# Count even numbers
print(count_by_predicate(numbers, lambda x: x % 2 == 0)) # Output: 3
You can combine count() with slicing, filtering, or other methods for nuanced queries.
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lst = [1, 2, 3, 1, 2, 1]
sublist = lst[2:5]
print(sublist.count(1)) # Output: 1 (only counts in sublist)
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lst = [1, 2, 3, 4, 5, 6]
even_numbers = [x for x in lst if x % 2 == 0]
print(even_numbers.count(4)) # Output: 1
Understanding differences in behavior is important.
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