CompTIA Network+ N10-009 IPv4 Addressing CIDR VLSM And Subnetting Practice Test
Objective 1.7 • 20 original questions
This CompTIA Network+ N10-009 practice test focuses on IPv4 addressing and subnetting. All questions are original ExamSnap scenarios aligned to the current N10-009 blueprint; they are not copied from CompTIA exam content. Use the complete N10-009 collection for broader practice across all five domains. For broader exam preparation, review the CompTIA Network+ N10-009 Exam Dumps page.
Instructions: Select the best answer for each question. Review the explanation after answering; each distractor includes a reason it is not the best choice for that scenario.
A network technician at Contoso Health needs the smallest IPv4 subnet that supports at least 200 usable host addresses. Which prefix length should be selected?
Correct answer: E
Why: A /24 provides 254 traditional usable host addresses. This is the smallest option that meets the requirement.
Option review:
A: A /26 provides 62 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
B: A /25 provides 126 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
C: A /23 provides 510 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
D: A /22 provides 1022 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
E: A /24 provides 254 traditional usable host addresses. This is the smallest option that meets the requirement.
Learning point: A /24 is the smallest conventional IPv4 subnet that provides at least 200 usable host addresses.
Host 172.20.201.132 is configured with prefix /26. Which network address contains this host?
Correct answer: E
Why: Applying the /26 mask to 172.20.201.132 yields network 172.20.201.128.
Option review:
A: 172.20.201.64 is not the network boundary for 172.20.201.132/26.
B: 172.20.201.192 is not the network boundary for 172.20.201.132/26.
C: 172.20.201.0 is not the network boundary for 172.20.201.132/26.
D: 172.20.202.0 is not the network boundary for 172.20.201.132/26.
E: Applying the /26 mask to 172.20.201.132 yields network 172.20.201.128.
Learning point: 172.20.201.132/26 belongs to network 172.20.201.128/26.
At Northwind Logistics, which IPv4 address is the broadcast address for subnet 192.168.99.16/28?
Correct answer: C
Why: 192.168.99.31 is the last address in the subnet and therefore the broadcast address.
Option review:
A: 192.168.99.30 is not the broadcast address for this subnet.
B: 192.168.99.16 is not the broadcast address for this subnet.
C: 192.168.99.31 is the last address in the subnet and therefore the broadcast address.
D: 192.168.99.32 is not the broadcast address for this subnet.
E: 192.168.99.17 is not the broadcast address for this subnet.
Learning point: The broadcast address of 192.168.99.16/28 is 192.168.99.31.
How should IPv4 address 127.0.0.1 be classified for Network+ troubleshooting purposes?
Correct answer: D
Why: 127.0.0.1 matches the Loopback/localhost category.
Option review:
A: 127.0.0.1 does not fall into the Class D / multicast range category.
B: 127.0.0.1 does not fall into the APIPA/link-local category.
C: 127.0.0.1 does not fall into the Public IPv4 address category.
D: 127.0.0.1 matches the Loopback/localhost category.
E: 127.0.0.1 does not fall into the RFC1918 private address category.
Learning point: 127.0.0.1 is classified as Loopback/localhost.
Adventure Works must divide a /24 network among departments needing different host capacities while minimizing wasted addresses. Which addressing technique best fits?
Correct answer: B
Why: Variable Length Subnet Masking allows different prefix sizes inside the address block to match different host needs.
Option review:
A: Loopback addressing does not efficiently create differently sized subnets from the available block.
B: Variable Length Subnet Masking allows different prefix sizes inside the address block to match different host needs.
C: Use one /24 for every department does not efficiently create differently sized subnets from the available block.
D: APIPA does not efficiently create differently sized subnets from the available block.
E: Classful addressing only does not efficiently create differently sized subnets from the available block.
Learning point: VLSM uses different prefix lengths to match subnet sizes to actual host requirements.
A field technician at Tailspin Toys needs the smallest IPv4 subnet that supports at least 30 usable host addresses. Which prefix length should be selected?
Correct answer: A
Why: A /27 provides 30 traditional usable host addresses. This is the smallest option that meets the requirement.
Option review:
A: A /27 provides 30 traditional usable host addresses. This is the smallest option that meets the requirement.
B: A /25 provides 126 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
C: A /29 provides 6 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
D: A /26 provides 62 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
E: A /28 provides 14 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
Learning point: A /27 is the smallest conventional IPv4 subnet that provides at least 30 usable host addresses.
Host 10.44.243.20 is configured with prefix /28. Which network address contains this host?
Correct answer: D
Why: Applying the /28 mask to 10.44.243.20 yields network 10.44.243.16.
Option review:
A: 10.44.243.0 is not the network boundary for 10.44.243.20/28.
B: 10.44.243.32 is not the network boundary for 10.44.243.20/28.
C: 10.44.243.48 is not the network boundary for 10.44.243.20/28.
D: Applying the /28 mask to 10.44.243.20 yields network 10.44.243.16.
E: 10.44.242.240 is not the network boundary for 10.44.243.20/28.
Learning point: 10.44.243.20/28 belongs to network 10.44.243.16/28.
At Proseware Media, which IPv4 address is the broadcast address for subnet 172.16.8.128/25?
Correct answer: E
Why: 172.16.8.255 is the last address in the subnet and therefore the broadcast address.
Option review:
A: 172.16.8.129 is not the broadcast address for this subnet.
B: 172.16.8.128 is not the broadcast address for this subnet.
C: 172.16.8.254 is not the broadcast address for this subnet.
D: 172.16.9.0 is not the broadcast address for this subnet.
E: 172.16.8.255 is the last address in the subnet and therefore the broadcast address.
Learning point: The broadcast address of 172.16.8.128/25 is 172.16.8.255.
How should IPv4 address 169.254.22.4 be classified for Network+ troubleshooting purposes?
Correct answer: A
Why: 169.254.22.4 matches the APIPA/link-local category.
Option review:
A: 169.254.22.4 matches the APIPA/link-local category.
B: 169.254.22.4 does not fall into the Class D / multicast range category.
C: 169.254.22.4 does not fall into the RFC1918 private address category.
D: 169.254.22.4 does not fall into the Public IPv4 address category.
E: 169.254.22.4 does not fall into the Loopback/localhost category.
Learning point: 169.254.22.4 is classified as APIPA/link-local.
Blue Yonder Airlines must divide a /24 network among departments needing different host capacities while minimizing wasted addresses. Which addressing technique best fits?
Correct answer: D
Why: Variable Length Subnet Masking allows different prefix sizes inside the address block to match different host needs.
Option review:
A: Loopback addressing does not efficiently create differently sized subnets from the available block.
B: APIPA does not efficiently create differently sized subnets from the available block.
C: Use one /24 for every department does not efficiently create differently sized subnets from the available block.
D: Variable Length Subnet Masking allows different prefix sizes inside the address block to match different host needs.
E: Classful addressing only does not efficiently create differently sized subnets from the available block.
Learning point: VLSM uses different prefix lengths to match subnet sizes to actual host requirements.
A network support specialist at Fourth Coffee needs the smallest IPv4 subnet that supports at least 500 usable host addresses. Which prefix length should be selected?
Correct answer: E
Why: A /23 provides 510 traditional usable host addresses. This is the smallest option that meets the requirement.
Option review:
A: A /25 provides 126 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
B: A /22 provides 1022 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
C: A /21 provides 2046 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
D: A /24 provides 254 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
E: A /23 provides 510 traditional usable host addresses. This is the smallest option that meets the requirement.
Learning point: A /23 is the smallest conventional IPv4 subnet that provides at least 500 usable host addresses.
Host 10.44.208.4 is configured with prefix /24. Which network address contains this host?
Correct answer: B
Why: Applying the /24 mask to 10.44.208.4 yields network 10.44.208.0.
Option review:
A: 10.44.209.0 is not the network boundary for 10.44.208.4/24.
B: Applying the /24 mask to 10.44.208.4 yields network 10.44.208.0.
C: 10.44.210.0 is not the network boundary for 10.44.208.4/24.
D: 10.44.207.0 is not the network boundary for 10.44.208.4/24.
E: 10.44.206.0 is not the network boundary for 10.44.208.4/24.
Learning point: 10.44.208.4/24 belongs to network 10.44.208.0/24.
At Contoso Health, which IPv4 address is the broadcast address for subnet 192.168.99.16/28?
Correct answer: A
Why: 192.168.99.31 is the last address in the subnet and therefore the broadcast address.
Option review:
A: 192.168.99.31 is the last address in the subnet and therefore the broadcast address.
B: 192.168.99.30 is not the broadcast address for this subnet.
C: 192.168.99.17 is not the broadcast address for this subnet.
D: 192.168.99.16 is not the broadcast address for this subnet.
E: 192.168.99.32 is not the broadcast address for this subnet.
Learning point: The broadcast address of 192.168.99.16/28 is 192.168.99.31.
How should IPv4 address 10.10.5.20 be classified for Network+ troubleshooting purposes?
Correct answer: A
Why: 10.10.5.20 matches the RFC1918 private address category.
Option review:
A: 10.10.5.20 matches the RFC1918 private address category.
B: 10.10.5.20 does not fall into the Public IPv4 address category.
C: 10.10.5.20 does not fall into the Loopback/localhost category.
D: 10.10.5.20 does not fall into the Class D / multicast range category.
E: 10.10.5.20 does not fall into the APIPA/link-local category.
Learning point: 10.10.5.20 is classified as RFC1918 private address.
Northwind Logistics must divide a /24 network among departments needing different host capacities while minimizing wasted addresses. Which addressing technique best fits?
Correct answer: B
Why: Variable Length Subnet Masking allows different prefix sizes inside the address block to match different host needs.
Option review:
A: Classful addressing only does not efficiently create differently sized subnets from the available block.
B: Variable Length Subnet Masking allows different prefix sizes inside the address block to match different host needs.
C: Loopback addressing does not efficiently create differently sized subnets from the available block.
D: APIPA does not efficiently create differently sized subnets from the available block.
E: Use one /24 for every department does not efficiently create differently sized subnets from the available block.
Learning point: VLSM uses different prefix lengths to match subnet sizes to actual host requirements.
A systems administrator at Litware Manufacturing needs the smallest IPv4 subnet that supports at least 50 usable host addresses. Which prefix length should be selected?
Correct answer: E
Why: A /26 provides 62 traditional usable host addresses. This is the smallest option that meets the requirement.
Option review:
A: A /24 provides 254 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
B: A /27 provides 30 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
C: A /25 provides 126 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
D: A /28 provides 14 traditional usable host addresses. It does not provide the smallest valid capacity for the requirement.
E: A /26 provides 62 traditional usable host addresses. This is the smallest option that meets the requirement.
Learning point: A /26 is the smallest conventional IPv4 subnet that provides at least 50 usable host addresses.
Host 10.20.245.4 is configured with prefix /25. Which network address contains this host?
Correct answer: D
Why: Applying the /25 mask to 10.20.245.4 yields network 10.20.245.0.
Option review:
A: 10.20.246.0 is not the network boundary for 10.20.245.4/25.
B: 10.20.244.0 is not the network boundary for 10.20.245.4/25.
C: 10.20.245.128 is not the network boundary for 10.20.245.4/25.
D: Applying the /25 mask to 10.20.245.4 yields network 10.20.245.0.
E: 10.20.244.128 is not the network boundary for 10.20.245.4/25.
Learning point: 10.20.245.4/25 belongs to network 10.20.245.0/25.
At Tailspin Toys, which IPv4 address is the broadcast address for subnet 192.168.10.64/26?
Correct answer: B
Why: 192.168.10.127 is the last address in the subnet and therefore the broadcast address.
Option review:
A: 192.168.10.65 is not the broadcast address for this subnet.
B: 192.168.10.127 is the last address in the subnet and therefore the broadcast address.
C: 192.168.10.126 is not the broadcast address for this subnet.
D: 192.168.10.128 is not the broadcast address for this subnet.
E: 192.168.10.64 is not the broadcast address for this subnet.
Learning point: The broadcast address of 192.168.10.64/26 is 192.168.10.127.
How should IPv4 address 172.20.3.9 be classified for Network+ troubleshooting purposes?
Correct answer: B
Why: 172.20.3.9 matches the RFC1918 private address category.
Option review:
A: 172.20.3.9 does not fall into the APIPA/link-local category.
B: 172.20.3.9 matches the RFC1918 private address category.
C: 172.20.3.9 does not fall into the Loopback/localhost category.
D: 172.20.3.9 does not fall into the Public IPv4 address category.
E: 172.20.3.9 does not fall into the Class D / multicast range category.
Learning point: 172.20.3.9 is classified as RFC1918 private address.
Proseware Media must divide a /24 network among departments needing different host capacities while minimizing wasted addresses. Which addressing technique best fits?
Correct answer: E
Why: Variable Length Subnet Masking allows different prefix sizes inside the address block to match different host needs.
Option review:
A: APIPA does not efficiently create differently sized subnets from the available block.
B: Loopback addressing does not efficiently create differently sized subnets from the available block.
C: Classful addressing only does not efficiently create differently sized subnets from the available block.
D: Use one /24 for every department does not efficiently create differently sized subnets from the available block.
E: Variable Length Subnet Masking allows different prefix sizes inside the address block to match different host needs.
Learning point: VLSM uses different prefix lengths to match subnet sizes to actual host requirements.
Popular posts
Recent Posts
