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Question 70
Two adjacent networks, 10.4.0.0/26 and 10.4.0.64/26, must be summarized exactly. Which supernet covers only those two?
- 10.4.0.0/25
- 10.4.0.0/26
- 10.4.0.64/25
- 10.4.0.0/24
Explanation
Correct Answer
A:Each /26 has 64 addresses; aligned adjacent .0 and .64 blocks combine to .0/25.
Incorrect Answers
B:This includes only the first of the two /26 blocks.
C:The .64 start is not a valid /25 boundary.
D:A /24 also includes .128–.255, outside the two networks.
Question 71
Two devices use 10.0.9.31/27 and 10.0.9.32/27 with no router. Can they communicate as same-subnet peers?
- Yes; .31 and .32 are consecutive addresses
- No; the addresses lie on different /27 blocks
- No; 10.0.9.32 is a public IPv4 address
- Yes; both are within 10.0.9.0/24
Explanation
Correct Answer
B:/27 ranges are .0–.31 and .32–.63; the two addresses are separated by a boundary, and .31 is broadcast.
Incorrect Answers
A:Adjacent numeric addresses can belong to separate IP subnets.
C:The 10/8 block is private; the issue is the subnet boundary and invalid network/broadcast roles.
D:Their shared /24 is irrelevant because each device uses a /27 mask.
Question 72
A subnet 172.16.0.0/20 is assigned to a server VLAN. Which last-octet/third-octet boundary correctly describes its address range?
- 172.16.0.0 through 172.16.7.255
- 172.16.0.0 through 172.16.31.255
- 172.16.0.0 through 172.16.16.255
- 172.16.0.0 through 172.16.15.255
Explanation
Correct Answer
D:A /20 covers 16 consecutive third-octet values, 0 through 15 here.
Incorrect Answers
A:Only eight third-octet blocks are covered, equivalent to /21.
B:That spans a /19, twice the intended /20.
C:The 16.x addresses belong to the following /20 block.
Question 73
A routing engineer sees an advertised IPv4 prefix 192.168.20.0/23. Which two /24 networks are contained in that prefix?
- 192.168.21.0/24 and 192.168.22.0/24
- 192.168.20.0/24 and 192.168.21.0/24
- 192.168.19.0/24 and 192.168.20.0/24
- 192.168.20.0/24 and 192.168.22.0/24
Explanation
Correct Answer
B:A /23 masks the last bit of the third octet; an even .20 start covers .20 and .21.
Incorrect Answers
A:The .22/24 lies in the following /23, not 192.168.20.0/23.
C:The /23 boundary must begin at an even third octet; .19 belongs to the previous block.
D:The two halves must be consecutive; the second is .21.
Question 74
A network administrator subdivides one IPv4 /24 into equally sized /28 subnets. How many distinct /28 networks result?
- 16
- 32
- 8
- 14
Explanation
Correct Answer
A:Borrowing four subnet bits (28−24) creates 2^4 = 16 equal subnets.
Incorrect Answers
B:Thirty-two results from borrowing five subnet bits, as with /29.
C:Eight results from borrowing three subnet bits, as with /27.
D:This incorrectly subtracts two host-reserved addresses from the number of subnets.
Question 75
A provider allocates one /27 and divides it into conventional /30 point-to-point subnets. How many /30 networks fit?
- 16
- 6
- 8
- 4
Explanation
Correct Answer
C:Moving from /27 to /30 adds three subnet bits, giving 2^3 = 8.
Incorrect Answers
A:Sixteen would require four additional subnet bits, not three.
B:This confuses usable host counts with the count of child subnets.
D:Four would be the number of /29 blocks inside /27.
Question 76
An address plan assigns 10.5.24.0/21 to a branch. Which third-octet span is inside that one network?
- 25 through 32
- 24 through 31
- 24 through 27
- 24 through 39
Explanation
Correct Answer
B:A /21 has a block size of eight in the third octet; .24 is an aligned boundary.
Incorrect Answers
A:The network starts with third octet 24 and ends before 32.
C:That is a /22-sized four-block range.
D:That spans 16 blocks, a /20-sized range.
Question 77
Routes 10.2.4.0/24 and 10.2.5.0/24 are adjacent and equally managed. Which summary exactly covers both?
- 10.2.5.0/23
- 10.2.4.0/22
- 10.2.4.0/23
- 10.2.4.0/24
Explanation
Correct Answer
C:An even .4 third-octet boundary allows .4 and .5 to aggregate into /23.
Incorrect Answers
A:A /23 must start at an even third-octet value; .5 is misaligned.
B:A /22 includes .4–.7, adding two unrequested /24s.
D:Only the first /24 is covered.
Question 78
An IPAM review proposes 10.1.16.0/23 for one team and 10.1.17.0/24 for another. What is the correct overlap finding?
- They overlap only at their broadcast addresses
- They overlap: the /23 includes all of 10.1.17.0/24
- Only address 10.1.17.0 overlaps
- They are disjoint because their third octets differ
Explanation
Correct Answer
B:10.1.16.0/23 spans 10.1.16.0–10.1.17.255.
Incorrect Answers
A:The overlap covers the entire /24, not only a reserved endpoint.
C:Every address in the second /24 is contained in the first /23.
D:A /23 spans two adjacent /24s, so differing third octets can still overlap.
Question 79
A host is 192.168.50.129/26 but its gateway is configured as 192.168.50.1. Which replacement gateway is on its connected subnet?
- 192.168.50.64
- 192.168.50.1
- 192.168.50.130
- 192.168.50.192
Explanation
Correct Answer
C:A /26 containing .129 has network .128 and usable range .129–.190.
Incorrect Answers
A:This address identifies the second /26 and is not on the .128/26 LAN.
B:This gateway belongs to the first /26, not the host’s fourth /26.
D:This is the network identifier of the next /26.
Question 80
An IOS standard ACL should match exactly one source IP, 10.10.10.50, rather than a subnet. Which wildcard value is correct?
- 0.0.0.255
- 0.0.0.0
- 255.255.255.255
- 0.0.0.1
Explanation
Correct Answer
B:All wildcard bits zero require every source-address bit to match.
Incorrect Answers
A:That matches all addresses in 10.10.10.0/24 with the corresponding base.
C:That wildcard ignores all 32 address bits instead of matching one host.
D:That allows variation in one address bit, matching two addresses.
Cisco Certified Network Associate (CCNA) (200-301) Practice Tests