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Question 60
An IT team allocates an ordinary IPv4 /27 to employee endpoints. How many usable host addresses does it provide?
- 31
- 62
- 30
- 32
Explanation
Correct Answer
C:A /27 has 5 host bits and 32 total addresses; subtract network and broadcast to get 30.
Incorrect Answers
A:One of the two reserved conventional /27 addresses remains incorrectly counted.
B:That is the conventional usable-host count of a /26, not a /27.
D:This counts the network identifier and directed broadcast as assignable hosts.
Question 61
An upstream router must configure a subnet mask for network 10.88.4.0/22. Which dotted-decimal mask is correct?
- 255.255.255.0
- 255.255.252.0
- 255.255.248.0
- 255.255.254.0
Explanation
Correct Answer
B:A /22 has six one-bits in the third octet, resulting in 252; the fourth octet is zero.
Incorrect Answers
A:That is /24 and splits the required /22 into four smaller networks.
C:That is /21 and covers twice as many addresses as /22.
D:That is /23 and covers only half of the required /22.
Question 62
A router interface displays IPv4 mask 255.255.255.240. Which CIDR prefix length matches?
- /28
- /27
- /29
- /26
Explanation
Correct Answer
A:The final mask octet 240 is binary 11110000, adding four bits to the first 24.
Incorrect Answers
B:A /27 has final mask octet 224 (11100000).
C:A /29 has final mask octet 248 (11111000).
D:A /26 has final mask octet 192 (11000000).
Question 63
An IOS access list must match exactly the /27 subnet 192.0.2.96/27. What wildcard mask is required?
- 0.0.0.63
- 0.0.0.31
- 0.0.0.15
- 255.255.255.224
Explanation
Correct Answer
B:The inverse of /27 subnet mask 255.255.255.224 is wildcard 0.0.0.31.
Incorrect Answers
A:This wildcard corresponds to a broader /26 match.
C:This wildcard corresponds to a narrower /28 match.
D:This is the forward subnet mask; IOS ACL address matching requires its inverse wildcard.
Question 64
A point-to-point LAN uses conventional IPv4 /30 192.0.2.4/30. Which pair is suitable for the router interfaces?
- 192.0.2.7 and 192.0.2.8
- 192.0.2.5 and 192.0.2.6
- 192.0.2.6 and 192.0.2.7
- 192.0.2.4 and 192.0.2.5
Explanation
Correct Answer
B:The four-address block is .4–.7; .5 and .6 are the two conventional usable hosts.
Incorrect Answers
A:The first is broadcast and the second is outside the assigned /30.
C:The .7 address is the /30 directed broadcast.
D:The .4 address is the /30 network identifier.
Question 65
A host in subnet 10.55.8.0/26 is configured with IPv4 address 10.55.8.63. What is the addressing fault?
- The host uses the subnet broadcast address
- The host is in the following /26
- The host uses the network identifier
- The host uses a public routable address
Explanation
Correct Answer
A:A /26 beginning at .0 ends at .63; that final address is reserved for broadcast.
Incorrect Answers
B:The next /26 starts at .64; .63 is still in the .0/26 block.
C:The network identifier is 10.55.8.0, not .63.
D:10.55.8.63 is within RFC1918 10.0.0.0/8, not ordinary public space.
Question 66
A laptop is set to 10.22.44.129 with prefix length /25. Which subnet must its default gateway share?
- 10.22.44.128/25
- 10.22.44.64/25
- 10.22.45.0/25
- 10.22.44.0/25
Explanation
Correct Answer
A:The /25 splits the /24 at .128; the laptop is on the upper /25.
Incorrect Answers
B:This is not an aligned /25 network boundary.
C:The laptop third octet is 44, not 45.
D:The lower /25 covers .0–.127 and excludes .129.
Question 67
An ordinary user subnet needs 70 usable IPv4 host addresses, with network and broadcast reserved. What is the smallest conventional prefix?
- /25
- /27
- /26
- /24
Explanation
Correct Answer
A:A /25 provides 126 usable hosts; /26 provides only 62.
Incorrect Answers
B:A /27 supports only 30 usable hosts.
C:A /26 supports only 62 usable hosts, below 70.
D:A /24 works but is larger than necessary; /25 is smaller and sufficient.
Question 68
A department needs 29 endpoints on one conventional IPv4 LAN. What is the narrowest prefix that still fits them?
- /28
- /27
- /25
- /29
Explanation
Correct Answer
B:A /27 has 30 usable host addresses; /28 has only 14.
Incorrect Answers
A:A /28 cannot accommodate 29 assigned hosts.
C:A /25 supports far more hosts than 29 and wastes address space relative to the sufficient /27.
D:A /29 allows only six conventional usable hosts.
Question 69
A VLSM plan already allocates 192.168.4.0/25. Which proposed /26 is the first nonoverlapping aligned block in that /24?
- 192.168.4.96/26
- 192.168.4.0/26
- 192.168.4.128/26
- 192.168.4.64/26
Explanation
Correct Answer
C:The first /25 occupies .0–.127; the next valid /26 begins at .128.
Incorrect Answers
A:A /26 must start at a multiple of 64; .96 is not aligned.
B:This lies inside the already allocated first /25.
D:This occupies .64–.127, wholly overlapping the existing /25.
Question 70
Two adjacent networks, 10.4.0.0/26 and 10.4.0.64/26, must be summarized exactly. Which supernet covers only those two?
- 10.4.0.0/25
- 10.4.0.0/26
- 10.4.0.64/25
- 10.4.0.0/24
Explanation
Correct Answer
A:Each /26 has 64 addresses; aligned adjacent .0 and .64 blocks combine to .0/25.
Incorrect Answers
B:This includes only the first of the two /26 blocks.
C:The .64 start is not a valid /25 boundary.
D:A /24 also includes .128–.255, outside the two networks.
Cisco Certified Network Associate (CCNA) (200-301) Practice Tests